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(D) For $I. [Ma_3b_2c]^{n \pm}$:There are $3$ geometrical isomers (all optically inactive). Total stereoisomers = $3$.For $II. [M(AB)_3]^{n \pm}$:Ther

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$3 - 4 - 6$

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(D) For $I. [Ma_3b_2c]^{n \pm}$:There are $3$ geometrical isomers (all optically inactive). Total stereoisomers = $3$.For $II. [M(AB)_3]^{n \pm}$:There are $2$ geometrical isomers (cis and trans). Both are optically active (each has $2$ enantiomers). Total stereoisomers = $2 + 2 = 4$.For $III. [Ma_2b_2c_2]^{n \pm}$:There are $6$ geometrical isomers. Only one cis-isomer is optically active (exists as a pair of enantiomers),while the other $5$ are optically inactive. Total stereoisomers = $5 + 1 = 6$.Thus,the correct sequence is $3 - 4 - 6$.

Select the correct code regarding the total number of stereoisomers for the following compounds:
$I. [Ma_3b_2c]^{n \pm}, II. [M(AB)_3]^{n \pm}, III. [Ma_2b_2c_2]^{n \pm}$
$I - II - III$

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Select the correct code regarding the total number of stereoisomers for the following compounds:$I. [Ma_3b_2c]^{n \pm}, II. [M(AB)_3]^{n \pm}, III. [Ma_2b_2c_2]^{n \pm}$$I - II - III$